6(4z-1)-3(z+4)=2(z+1)

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Solution for 6(4z-1)-3(z+4)=2(z+1) equation:


Simplifying
6(4z + -1) + -3(z + 4) = 2(z + 1)

Reorder the terms:
6(-1 + 4z) + -3(z + 4) = 2(z + 1)
(-1 * 6 + 4z * 6) + -3(z + 4) = 2(z + 1)
(-6 + 24z) + -3(z + 4) = 2(z + 1)

Reorder the terms:
-6 + 24z + -3(4 + z) = 2(z + 1)
-6 + 24z + (4 * -3 + z * -3) = 2(z + 1)
-6 + 24z + (-12 + -3z) = 2(z + 1)

Reorder the terms:
-6 + -12 + 24z + -3z = 2(z + 1)

Combine like terms: -6 + -12 = -18
-18 + 24z + -3z = 2(z + 1)

Combine like terms: 24z + -3z = 21z
-18 + 21z = 2(z + 1)

Reorder the terms:
-18 + 21z = 2(1 + z)
-18 + 21z = (1 * 2 + z * 2)
-18 + 21z = (2 + 2z)

Solving
-18 + 21z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-18 + 21z + -2z = 2 + 2z + -2z

Combine like terms: 21z + -2z = 19z
-18 + 19z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-18 + 19z = 2 + 0
-18 + 19z = 2

Add '18' to each side of the equation.
-18 + 18 + 19z = 2 + 18

Combine like terms: -18 + 18 = 0
0 + 19z = 2 + 18
19z = 2 + 18

Combine like terms: 2 + 18 = 20
19z = 20

Divide each side by '19'.
z = 1.052631579

Simplifying
z = 1.052631579

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