6(4z-1)-2(z+3)=19(z+1)

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Solution for 6(4z-1)-2(z+3)=19(z+1) equation:


Simplifying
6(4z + -1) + -2(z + 3) = 19(z + 1)

Reorder the terms:
6(-1 + 4z) + -2(z + 3) = 19(z + 1)
(-1 * 6 + 4z * 6) + -2(z + 3) = 19(z + 1)
(-6 + 24z) + -2(z + 3) = 19(z + 1)

Reorder the terms:
-6 + 24z + -2(3 + z) = 19(z + 1)
-6 + 24z + (3 * -2 + z * -2) = 19(z + 1)
-6 + 24z + (-6 + -2z) = 19(z + 1)

Reorder the terms:
-6 + -6 + 24z + -2z = 19(z + 1)

Combine like terms: -6 + -6 = -12
-12 + 24z + -2z = 19(z + 1)

Combine like terms: 24z + -2z = 22z
-12 + 22z = 19(z + 1)

Reorder the terms:
-12 + 22z = 19(1 + z)
-12 + 22z = (1 * 19 + z * 19)
-12 + 22z = (19 + 19z)

Solving
-12 + 22z = 19 + 19z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-19z' to each side of the equation.
-12 + 22z + -19z = 19 + 19z + -19z

Combine like terms: 22z + -19z = 3z
-12 + 3z = 19 + 19z + -19z

Combine like terms: 19z + -19z = 0
-12 + 3z = 19 + 0
-12 + 3z = 19

Add '12' to each side of the equation.
-12 + 12 + 3z = 19 + 12

Combine like terms: -12 + 12 = 0
0 + 3z = 19 + 12
3z = 19 + 12

Combine like terms: 19 + 12 = 31
3z = 31

Divide each side by '3'.
z = 10.33333333

Simplifying
z = 10.33333333

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