6(4x-9)-6=6(x-3)+48

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Solution for 6(4x-9)-6=6(x-3)+48 equation: 



6(4x-9)-6=6(x-3)+48

We move all terms to the left:

6(4x-9)-6-(6(x-3)+48)=0

We multiply parentheses

24x-(6(x-3)+48)-54-6=0



We calculate terms in parentheses: -(6(x-3)+48), so:

6(x-3)+48

We multiply parentheses

6x-18+48

We add all the numbers together, and all the variables

6x+30

Back to the equation:

-(6x+30)



We add all the numbers together, and all the variables

24x-(6x+30)-60=0

We get rid of parentheses

24x-6x-30-60=0

We add all the numbers together, and all the variables

18x-90=0

We move all terms containing x to the left, all other terms to the right

18x=90

x=90/18

x=5

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