6(4x-5)=20x+2

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Solution for 6(4x-5)=20x+2 equation: 



6(4x-5)=20x+2

We move all terms to the left:

6(4x-5)-(20x+2)=0

We multiply parentheses

24x-(20x+2)-30=0

We get rid of parentheses

24x-20x-2-30=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8

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