6(4x-3)-4(2x-10)=3(5x+5)-12

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Solution for 6(4x-3)-4(2x-10)=3(5x+5)-12 equation: 



6(4x-3)-4(2x-10)=3(5x+5)-12

We move all terms to the left:

6(4x-3)-4(2x-10)-(3(5x+5)-12)=0

We multiply parentheses

24x-8x-(3(5x+5)-12)-18+40=0



We calculate terms in parentheses: -(3(5x+5)-12), so:

3(5x+5)-12

We multiply parentheses

15x+15-12

We add all the numbers together, and all the variables

15x+3

Back to the equation:

-(15x+3)



We add all the numbers together, and all the variables

16x-(15x+3)+22=0

We get rid of parentheses

16x-15x-3+22=0

We add all the numbers together, and all the variables

x+19=0

We move all terms containing x to the left, all other terms to the right

x=-19

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