6(4x-3)+3=(4x-1)

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Solution for 6(4x-3)+3=(4x-1) equation: 



6(4x-3)+3=(4x-1)

We move all terms to the left:

6(4x-3)+3-((4x-1))=0

We multiply parentheses

24x-((4x-1))-18+3=0



We calculate terms in parentheses: -((4x-1)), so:

(4x-1)

We get rid of parentheses

4x-1

Back to the equation:

-(4x-1)



We add all the numbers together, and all the variables

24x-(4x-1)-15=0

We get rid of parentheses

24x-4x+1-15=0

We add all the numbers together, and all the variables

20x-14=0

We move all terms containing x to the left, all other terms to the right

20x=14

x=14/20

x=7/10

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