6(4x-2)+4(9-2x)-5(3x+3)=-8

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Solution for 6(4x-2)+4(9-2x)-5(3x+3)=-8 equation: 



6(4x-2)+4(9-2x)-5(3x+3)=-8

We move all terms to the left:

6(4x-2)+4(9-2x)-5(3x+3)-(-8)=0

We add all the numbers together, and all the variables

6(4x-2)+4(-2x+9)-5(3x+3)-(-8)=0

We add all the numbers together, and all the variables

6(4x-2)+4(-2x+9)-5(3x+3)+8=0

We multiply parentheses

24x-8x-15x-12+36-15+8=0

We add all the numbers together, and all the variables

x+17=0

We move all terms containing x to the left, all other terms to the right

x=-17

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