6(4x-2)+3(8x-5)=2(9x+18)+6x+9

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Solution for 6(4x-2)+3(8x-5)=2(9x+18)+6x+9 equation: 



6(4x-2)+3(8x-5)=2(9x+18)+6x+9

We move all terms to the left:

6(4x-2)+3(8x-5)-(2(9x+18)+6x+9)=0

We multiply parentheses

24x+24x-(2(9x+18)+6x+9)-12-15=0



We calculate terms in parentheses: -(2(9x+18)+6x+9), so:

2(9x+18)+6x+9

We add all the numbers together, and all the variables

6x+2(9x+18)+9

We multiply parentheses

6x+18x+36+9

We add all the numbers together, and all the variables

24x+45

Back to the equation:

-(24x+45)



We add all the numbers together, and all the variables

48x-(24x+45)-27=0

We get rid of parentheses

48x-24x-45-27=0

We add all the numbers together, and all the variables

24x-72=0

We move all terms containing x to the left, all other terms to the right

24x=72

x=72/24

x=3

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