6(4n-7)=4(2n+1)

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Solution for 6(4n-7)=4(2n+1) equation: 



6(4n-7)=4(2n+1)

We move all terms to the left:

6(4n-7)-(4(2n+1))=0

We multiply parentheses

24n-(4(2n+1))-42=0



We calculate terms in parentheses: -(4(2n+1)), so:

4(2n+1)

We multiply parentheses

8n+4

Back to the equation:

-(8n+4)



We get rid of parentheses

24n-8n-4-42=0

We add all the numbers together, and all the variables

16n-46=0

We move all terms containing n to the left, all other terms to the right

16n=46

n=46/16

n=2+7/8

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