6(4c+2)=20c+40

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Solution for 6(4c+2)=20c+40 equation: 



6(4c+2)=20c+40

We move all terms to the left:

6(4c+2)-(20c+40)=0

We multiply parentheses

24c-(20c+40)+12=0

We get rid of parentheses

24c-20c-40+12=0

We add all the numbers together, and all the variables

4c-28=0

We move all terms containing c to the left, all other terms to the right

4c=28

c=28/4

c=7

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