6(4b-4)+10(b-6)=123

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Solution for 6(4b-4)+10(b-6)=123 equation: 



6(4b-4)+10(b-6)=123

We move all terms to the left:

6(4b-4)+10(b-6)-(123)=0

We multiply parentheses

24b+10b-24-60-123=0

We add all the numbers together, and all the variables

34b-207=0

We move all terms containing b to the left, all other terms to the right

34b=207

b=207/34

b=6+3/34

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