6(4b-10)=b+8(3b+7)

Solution for 6(4b-10)=b+8(3b+7) equation:

6(4b-10)=b+8(3b+7)

We move all terms to the left:

6(4b-10)-(b+8(3b+7))=0

We multiply parentheses

24b-(b+8(3b+7))-60=0


We calculate terms in parentheses: -(b+8(3b+7)), so:

b+8(3b+7)

We multiply parentheses

b+24b+56

We add all the numbers together, and all the variables

25b+56

Back to the equation:

-(25b+56)


We get rid of parentheses

24b-25b-56-60=0

We add all the numbers together, and all the variables

-1b-116=0

We move all terms containing b to the left, all other terms to the right

-b=116

b=116/-1

b=-116