6(42z-7)=30

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Solution for 6(42z-7)=30 equation: 



6(42z-7)=30

We move all terms to the left:

6(42z-7)-(30)=0

We multiply parentheses

252z-42-30=0

We add all the numbers together, and all the variables

252z-72=0

We move all terms containing z to the left, all other terms to the right

252z=72

z=72/252

z=2/7

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