6(4-z)/5=z

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Solution for 6(4-z)/5=z equation: 



6(4-z)/5=z

We move all terms to the left:

6(4-z)/5-(z)=0

We add all the numbers together, and all the variables

6(-1z+4)/5-z=0

We add all the numbers together, and all the variables

-1z+6(-1z+4)/5=0

We multiply all the terms by the denominator


-1z*5+6(-1z+4)=0

We multiply parentheses

-1z*5-6z+24=0

Wy multiply elements

-5z-6z+24=0

We add all the numbers together, and all the variables

-11z+24=0

We move all terms containing z to the left, all other terms to the right

-11z=-24

z=-24/-11

z=2+2/11

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