6(4-x)-(2x+2)=8+6(x-7)

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Solution for 6(4-x)-(2x+2)=8+6(x-7) equation: 



6(4-x)-(2x+2)=8+6(x-7)

We move all terms to the left:

6(4-x)-(2x+2)-(8+6(x-7))=0

We add all the numbers together, and all the variables

6(-1x+4)-(2x+2)-(8+6(x-7))=0

We multiply parentheses

-6x-(2x+2)-(8+6(x-7))+24=0

We get rid of parentheses

-6x-2x-(8+6(x-7))-2+24=0



We calculate terms in parentheses: -(8+6(x-7)), so:

8+6(x-7)

determiningTheFunctionDomain
6(x-7)+8

We multiply parentheses

6x-42+8

We add all the numbers together, and all the variables

6x-34

Back to the equation:

-(6x-34)



We add all the numbers together, and all the variables

-8x-(6x-34)+22=0

We get rid of parentheses

-8x-6x+34+22=0

We add all the numbers together, and all the variables

-14x+56=0

We move all terms containing x to the left, all other terms to the right

-14x=-56

x=-56/-14

x=+4

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