6(4-2x)=5(3+2x)

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Solution for 6(4-2x)=5(3+2x) equation:



6(4-2x)=5(3+2x)
We move all terms to the left:
6(4-2x)-(5(3+2x))=0
We add all the numbers together, and all the variables
6(-2x+4)-(5(2x+3))=0
We multiply parentheses
-12x-(5(2x+3))+24=0
We calculate terms in parentheses: -(5(2x+3)), so:
5(2x+3)
We multiply parentheses
10x+15
Back to the equation:
-(10x+15)
We get rid of parentheses
-12x-10x-15+24=0
We add all the numbers together, and all the variables
-22x+9=0
We move all terms containing x to the left, all other terms to the right
-22x=-9
x=-9/-22
x=9/22

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