6(4-2x)+(-20)=10-3(6x-2)

Solution for 6(4-2x)+(-20)=10-3(6x-2) equation:

6(4-2x)+(-20)=10-3(6x-2)

We move all terms to the left:

6(4-2x)+(-20)-(10-3(6x-2))=0

We add all the numbers together, and all the variables

6(-2x+4)-(10-3(6x-2))+(-20)=0

We add all the numbers together, and all the variables

6(-2x+4)-(10-3(6x-2))-20=0

We multiply parentheses

-12x-(10-3(6x-2))+24-20=0


We calculate terms in parentheses: -(10-3(6x-2)), so:

10-3(6x-2)

determiningTheFunctionDomain
-3(6x-2)+10

We multiply parentheses

-18x+6+10

We add all the numbers together, and all the variables

-18x+16

Back to the equation:

-(-18x+16)


We add all the numbers together, and all the variables

-12x-(-18x+16)+4=0

We get rid of parentheses

-12x+18x-16+4=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2