6(4+x)-1=27-(1x+5)

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Solution for 6(4+x)-1=27-(1x+5) equation: 



6(4+x)-1=27-(1x+5)

We move all terms to the left:

6(4+x)-1-(27-(1x+5))=0

We add all the numbers together, and all the variables

6(x+4)-(27-(x+5))-1=0

We multiply parentheses

6x-(27-(x+5))+24-1=0



We calculate terms in parentheses: -(27-(x+5)), so:

27-(x+5)

determiningTheFunctionDomain
-(x+5)+27

We get rid of parentheses

-x-5+27

We add all the numbers together, and all the variables

-1x+22

Back to the equation:

-(-1x+22)



We add all the numbers together, and all the variables

6x-(-1x+22)+23=0

We get rid of parentheses

6x+1x-22+23=0

We add all the numbers together, and all the variables

7x+1=0

We move all terms containing x to the left, all other terms to the right

7x=-1

x=-1/7

x=-1/7

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