6(4+c)=5(2+c)

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Solution for 6(4+c)=5(2+c) equation: 



6(4+c)=5(2+c)

We move all terms to the left:

6(4+c)-(5(2+c))=0

We add all the numbers together, and all the variables

6(c+4)-(5(c+2))=0

We multiply parentheses

6c-(5(c+2))+24=0



We calculate terms in parentheses: -(5(c+2)), so:

5(c+2)

We multiply parentheses

5c+10

Back to the equation:

-(5c+10)



We get rid of parentheses

6c-5c-10+24=0

We add all the numbers together, and all the variables

c+14=0

We move all terms containing c to the left, all other terms to the right

c=-14

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