6(4+8c)=3(3c+9)

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Solution for 6(4+8c)=3(3c+9) equation: 



6(4+8c)=3(3c+9)

We move all terms to the left:

6(4+8c)-(3(3c+9))=0

We add all the numbers together, and all the variables

6(8c+4)-(3(3c+9))=0

We multiply parentheses

48c-(3(3c+9))+24=0



We calculate terms in parentheses: -(3(3c+9)), so:

3(3c+9)

We multiply parentheses

9c+27

Back to the equation:

-(9c+27)



We get rid of parentheses

48c-9c-27+24=0

We add all the numbers together, and all the variables

39c-3=0

We move all terms containing c to the left, all other terms to the right

39c=3

c=3/39

c=1/13

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