6(4+5a)+10a=10(1-6a)-6

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Solution for 6(4+5a)+10a=10(1-6a)-6 equation: 



6(4+5a)+10a=10(1-6a)-6

We move all terms to the left:

6(4+5a)+10a-(10(1-6a)-6)=0

We add all the numbers together, and all the variables

6(5a+4)+10a-(10(-6a+1)-6)=0

We add all the numbers together, and all the variables

10a+6(5a+4)-(10(-6a+1)-6)=0

We multiply parentheses

10a+30a-(10(-6a+1)-6)+24=0



We calculate terms in parentheses: -(10(-6a+1)-6), so:

10(-6a+1)-6

We multiply parentheses

-60a+10-6

We add all the numbers together, and all the variables

-60a+4

Back to the equation:

-(-60a+4)



We add all the numbers together, and all the variables

40a-(-60a+4)+24=0

We get rid of parentheses

40a+60a-4+24=0

We add all the numbers together, and all the variables

100a+20=0

We move all terms containing a to the left, all other terms to the right

100a=-20

a=-20/100

a=-1/5

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