6(4+3c)=42

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Solution for 6(4+3c)=42 equation: 



6(4+3c)=42

We move all terms to the left:

6(4+3c)-(42)=0

We add all the numbers together, and all the variables

6(3c+4)-42=0

We multiply parentheses

18c+24-42=0

We add all the numbers together, and all the variables

18c-18=0

We move all terms containing c to the left, all other terms to the right

18c=18

c=18/18

c=1

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