6(3z-7)=17

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Solution for 6(3z-7)=17 equation: 



6(3z-7)=17

We move all terms to the left:

6(3z-7)-(17)=0

We multiply parentheses

18z-42-17=0

We add all the numbers together, and all the variables

18z-59=0

We move all terms containing z to the left, all other terms to the right

18z=59

z=59/18

z=3+5/18

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