6(3z-1)-5(z+2)=2(z+1)

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Solution for 6(3z-1)-5(z+2)=2(z+1) equation:


Simplifying
6(3z + -1) + -5(z + 2) = 2(z + 1)

Reorder the terms:
6(-1 + 3z) + -5(z + 2) = 2(z + 1)
(-1 * 6 + 3z * 6) + -5(z + 2) = 2(z + 1)
(-6 + 18z) + -5(z + 2) = 2(z + 1)

Reorder the terms:
-6 + 18z + -5(2 + z) = 2(z + 1)
-6 + 18z + (2 * -5 + z * -5) = 2(z + 1)
-6 + 18z + (-10 + -5z) = 2(z + 1)

Reorder the terms:
-6 + -10 + 18z + -5z = 2(z + 1)

Combine like terms: -6 + -10 = -16
-16 + 18z + -5z = 2(z + 1)

Combine like terms: 18z + -5z = 13z
-16 + 13z = 2(z + 1)

Reorder the terms:
-16 + 13z = 2(1 + z)
-16 + 13z = (1 * 2 + z * 2)
-16 + 13z = (2 + 2z)

Solving
-16 + 13z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-16 + 13z + -2z = 2 + 2z + -2z

Combine like terms: 13z + -2z = 11z
-16 + 11z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-16 + 11z = 2 + 0
-16 + 11z = 2

Add '16' to each side of the equation.
-16 + 16 + 11z = 2 + 16

Combine like terms: -16 + 16 = 0
0 + 11z = 2 + 16
11z = 2 + 16

Combine like terms: 2 + 16 = 18
11z = 18

Divide each side by '11'.
z = 1.636363636

Simplifying
z = 1.636363636

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