6(3z-1)-3(z+8)=8(z+1)

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Solution for 6(3z-1)-3(z+8)=8(z+1) equation: 



6(3z-1)-3(z+8)=8(z+1)

We move all terms to the left:

6(3z-1)-3(z+8)-(8(z+1))=0

We multiply parentheses

18z-3z-(8(z+1))-6-24=0



We calculate terms in parentheses: -(8(z+1)), so:

8(z+1)

We multiply parentheses

8z+8

Back to the equation:

-(8z+8)



We add all the numbers together, and all the variables

15z-(8z+8)-30=0

We get rid of parentheses

15z-8z-8-30=0

We add all the numbers together, and all the variables

7z-38=0

We move all terms containing z to the left, all other terms to the right

7z=38

z=38/7

z=5+3/7

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