6(3z+2)=4(6z+6)

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Solution for 6(3z+2)=4(6z+6) equation: 



6(3z+2)=4(6z+6)

We move all terms to the left:

6(3z+2)-(4(6z+6))=0

We multiply parentheses

18z-(4(6z+6))+12=0



We calculate terms in parentheses: -(4(6z+6)), so:

4(6z+6)

We multiply parentheses

24z+24

Back to the equation:

-(24z+24)



We get rid of parentheses

18z-24z-24+12=0

We add all the numbers together, and all the variables

-6z-12=0

We move all terms containing z to the left, all other terms to the right

-6z=12

z=12/-6

z=-2

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