6(3y-10)=7(11-2y)

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Solution for 6(3y-10)=7(11-2y) equation:



6(3y-10)=7(11-2y)
We move all terms to the left:
6(3y-10)-(7(11-2y))=0
We add all the numbers together, and all the variables
6(3y-10)-(7(-2y+11))=0
We multiply parentheses
18y-(7(-2y+11))-60=0
We calculate terms in parentheses: -(7(-2y+11)), so:
7(-2y+11)
We multiply parentheses
-14y+77
Back to the equation:
-(-14y+77)
We get rid of parentheses
18y+14y-77-60=0
We add all the numbers together, and all the variables
32y-137=0
We move all terms containing y to the left, all other terms to the right
32y=137
y=137/32
y=4+9/32

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