6(3y+2)=4(7y-11)

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Solution for 6(3y+2)=4(7y-11) equation:



6(3y+2)=4(7y-11)
We move all terms to the left:
6(3y+2)-(4(7y-11))=0
We multiply parentheses
18y-(4(7y-11))+12=0
We calculate terms in parentheses: -(4(7y-11)), so:
4(7y-11)
We multiply parentheses
28y-44
Back to the equation:
-(28y-44)
We get rid of parentheses
18y-28y+44+12=0
We add all the numbers together, and all the variables
-10y+56=0
We move all terms containing y to the left, all other terms to the right
-10y=-56
y=-56/-10
y=5+3/5

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