6(3x/2+4)-10=12(4x+16)

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Solution for 6(3x/2+4)-10=12(4x+16) equation: 



6(3x/2+4)-10=12(4x+16)

We move all terms to the left:

6(3x/2+4)-10-(12(4x+16))=0

We multiply parentheses

18x-(12(4x+16))+24-10=0



We calculate terms in parentheses: -(12(4x+16)), so:

12(4x+16)

We multiply parentheses

48x+192

Back to the equation:

-(48x+192)



We add all the numbers together, and all the variables

18x-(48x+192)+14=0

We get rid of parentheses

18x-48x-192+14=0

We add all the numbers together, and all the variables

-30x-178=0

We move all terms containing x to the left, all other terms to the right

-30x=178

x=178/-30

x=-5+14/15

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