6(3x-7)-4=6(x-3)+44

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Solution for 6(3x-7)-4=6(x-3)+44 equation: 



6(3x-7)-4=6(x-3)+44

We move all terms to the left:

6(3x-7)-4-(6(x-3)+44)=0

We multiply parentheses

18x-(6(x-3)+44)-42-4=0



We calculate terms in parentheses: -(6(x-3)+44), so:

6(x-3)+44

We multiply parentheses

6x-18+44

We add all the numbers together, and all the variables

6x+26

Back to the equation:

-(6x+26)



We add all the numbers together, and all the variables

18x-(6x+26)-46=0

We get rid of parentheses

18x-6x-26-46=0

We add all the numbers together, and all the variables

12x-72=0

We move all terms containing x to the left, all other terms to the right

12x=72

x=72/12

x=6

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