6(3x-7)-3=6(x-2)+39

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Solution for 6(3x-7)-3=6(x-2)+39 equation: 



6(3x-7)-3=6(x-2)+39

We move all terms to the left:

6(3x-7)-3-(6(x-2)+39)=0

We multiply parentheses

18x-(6(x-2)+39)-42-3=0



We calculate terms in parentheses: -(6(x-2)+39), so:

6(x-2)+39

We multiply parentheses

6x-12+39

We add all the numbers together, and all the variables

6x+27

Back to the equation:

-(6x+27)



We add all the numbers together, and all the variables

18x-(6x+27)-45=0

We get rid of parentheses

18x-6x-27-45=0

We add all the numbers together, and all the variables

12x-72=0

We move all terms containing x to the left, all other terms to the right

12x=72

x=72/12

x=6

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