6(3x-4)=3(2x+1)

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Solution for 6(3x-4)=3(2x+1) equation:



6(3x-4)=3(2x+1)
We move all terms to the left:
6(3x-4)-(3(2x+1))=0
We multiply parentheses
18x-(3(2x+1))-24=0
We calculate terms in parentheses: -(3(2x+1)), so:
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
We get rid of parentheses
18x-6x-3-24=0
We add all the numbers together, and all the variables
12x-27=0
We move all terms containing x to the left, all other terms to the right
12x=27
x=27/12
x=2+1/4

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