6(3x-4)+4(-4x-2)=4(x-3)

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Solution for 6(3x-4)+4(-4x-2)=4(x-3) equation: 



6(3x-4)+4(-4x-2)=4(x-3)

We move all terms to the left:

6(3x-4)+4(-4x-2)-(4(x-3))=0

We multiply parentheses

18x-16x-(4(x-3))-24-8=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

2x-(4x-12)-32=0

We get rid of parentheses

2x-4x+12-32=0

We add all the numbers together, and all the variables

-2x-20=0

We move all terms containing x to the left, all other terms to the right

-2x=20

x=20/-2

x=-10

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