6(3x-2)-3(4x-5)=33

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Solution for 6(3x-2)-3(4x-5)=33 equation: 



6(3x-2)-3(4x-5)=33

We move all terms to the left:

6(3x-2)-3(4x-5)-(33)=0

We multiply parentheses

18x-12x-12+15-33=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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