6(3x-2)+5(x-4)-7x=0

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Solution for 6(3x-2)+5(x-4)-7x=0 equation: 



6(3x-2)+5(x-4)-7x=0

We add all the numbers together, and all the variables

-7x+6(3x-2)+5(x-4)=0

We multiply parentheses

-7x+18x+5x-12-20=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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