6(3x-2)+4(x-5)=78

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Solution for 6(3x-2)+4(x-5)=78 equation: 



6(3x-2)+4(x-5)=78

We move all terms to the left:

6(3x-2)+4(x-5)-(78)=0

We multiply parentheses

18x+4x-12-20-78=0

We add all the numbers together, and all the variables

22x-110=0

We move all terms containing x to the left, all other terms to the right

22x=110

x=110/22

x=5

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