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6(3x-2)+2(x+4)=5(2x-1)+3(6x+5)
We move all terms to the left:
6(3x-2)+2(x+4)-(5(2x-1)+3(6x+5))=0
We multiply parentheses
18x+2x-(5(2x-1)+3(6x+5))-12+8=0
We calculate terms in parentheses: -(5(2x-1)+3(6x+5)), so:We add all the numbers together, and all the variables
5(2x-1)+3(6x+5)
We multiply parentheses
10x+18x-5+15
We add all the numbers together, and all the variables
28x+10
Back to the equation:
-(28x+10)
20x-(28x+10)-4=0
We get rid of parentheses
20x-28x-10-4=0
We add all the numbers together, and all the variables
-8x-14=0
We move all terms containing x to the left, all other terms to the right
-8x=14
x=14/-8
x=-1+3/4
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