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6(3x+9)-11=6(x+5)+1
We move all terms to the left:
6(3x+9)-11-(6(x+5)+1)=0
We multiply parentheses
18x-(6(x+5)+1)+54-11=0
We calculate terms in parentheses: -(6(x+5)+1), so:We add all the numbers together, and all the variables
6(x+5)+1
We multiply parentheses
6x+30+1
We add all the numbers together, and all the variables
6x+31
Back to the equation:
-(6x+31)
18x-(6x+31)+43=0
We get rid of parentheses
18x-6x-31+43=0
We add all the numbers together, and all the variables
12x+12=0
We move all terms containing x to the left, all other terms to the right
12x=-12
x=-12/12
x=-1
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