6(3x+5)=7(9x+3)+8

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Solution for 6(3x+5)=7(9x+3)+8 equation: 



6(3x+5)=7(9x+3)+8

We move all terms to the left:

6(3x+5)-(7(9x+3)+8)=0

We multiply parentheses

18x-(7(9x+3)+8)+30=0



We calculate terms in parentheses: -(7(9x+3)+8), so:

7(9x+3)+8

We multiply parentheses

63x+21+8

We add all the numbers together, and all the variables

63x+29

Back to the equation:

-(63x+29)



We get rid of parentheses

18x-63x-29+30=0

We add all the numbers together, and all the variables

-45x+1=0

We move all terms containing x to the left, all other terms to the right

-45x=-1

x=-1/-45

x=1/45

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