6(3x+5)=32+7x

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Solution for 6(3x+5)=32+7x equation: 



6(3x+5)=32+7x

We move all terms to the left:

6(3x+5)-(32+7x)=0

We add all the numbers together, and all the variables

6(3x+5)-(7x+32)=0

We multiply parentheses

18x-(7x+32)+30=0

We get rid of parentheses

18x-7x-32+30=0

We add all the numbers together, and all the variables

11x-2=0

We move all terms containing x to the left, all other terms to the right

11x=2

x=2/11

x=2/11

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