6(3x+5)-32=12-4(2x-1)

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Solution for 6(3x+5)-32=12-4(2x-1) equation: 



6(3x+5)-32=12-4(2x-1)

We move all terms to the left:

6(3x+5)-32-(12-4(2x-1))=0

We multiply parentheses

18x-(12-4(2x-1))+30-32=0



We calculate terms in parentheses: -(12-4(2x-1)), so:

12-4(2x-1)

determiningTheFunctionDomain
-4(2x-1)+12

We multiply parentheses

-8x+4+12

We add all the numbers together, and all the variables

-8x+16

Back to the equation:

-(-8x+16)



We add all the numbers together, and all the variables

18x-(-8x+16)-2=0

We get rid of parentheses

18x+8x-16-2=0

We add all the numbers together, and all the variables

26x-18=0

We move all terms containing x to the left, all other terms to the right

26x=18

x=18/26

x=9/13

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