6(3x+4)=-8(2-x)

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Solution for 6(3x+4)=-8(2-x) equation: 



6(3x+4)=-8(2-x)

We move all terms to the left:

6(3x+4)-(-8(2-x))=0

We add all the numbers together, and all the variables

6(3x+4)-(-8(-1x+2))=0

We multiply parentheses

18x-(-8(-1x+2))+24=0



We calculate terms in parentheses: -(-8(-1x+2)), so:

-8(-1x+2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

18x-8x+16+24=0

We add all the numbers together, and all the variables

10x+40=0

We move all terms containing x to the left, all other terms to the right

10x=-40

x=-40/10

x=-4

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