6(3x+2)=4(x-4)

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Solution for 6(3x+2)=4(x-4) equation: 



6(3x+2)=4(x-4)

We move all terms to the left:

6(3x+2)-(4(x-4))=0

We multiply parentheses

18x-(4(x-4))+12=0



We calculate terms in parentheses: -(4(x-4)), so:

4(x-4)

We multiply parentheses

4x-16

Back to the equation:

-(4x-16)



We get rid of parentheses

18x-4x+16+12=0

We add all the numbers together, and all the variables

14x+28=0

We move all terms containing x to the left, all other terms to the right

14x=-28

x=-28/14

x=-2

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