6(3x+2)=3(2x-4)

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Solution for 6(3x+2)=3(2x-4) equation: 



6(3x+2)=3(2x-4)

We move all terms to the left:

6(3x+2)-(3(2x-4))=0

We multiply parentheses

18x-(3(2x-4))+12=0



We calculate terms in parentheses: -(3(2x-4)), so:

3(2x-4)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

18x-6x+12+12=0

We add all the numbers together, and all the variables

12x+24=0

We move all terms containing x to the left, all other terms to the right

12x=-24

x=-24/12

x=-2

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