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6(3x+2)=2(9x+6)
We move all terms to the left:
6(3x+2)-(2(9x+6))=0
We multiply parentheses
18x-(2(9x+6))+12=0
We calculate terms in parentheses: -(2(9x+6)), so:We get rid of parentheses
2(9x+6)
We multiply parentheses
18x+12
Back to the equation:
-(18x+12)
18x-18x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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