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6(3x+2)-5(6x-3)=6(x-3)-5(7x-6)+12x
We move all terms to the left:
6(3x+2)-5(6x-3)-(6(x-3)-5(7x-6)+12x)=0
We multiply parentheses
18x-30x-(6(x-3)-5(7x-6)+12x)+12+15=0
We calculate terms in parentheses: -(6(x-3)-5(7x-6)+12x), so:We add all the numbers together, and all the variables
6(x-3)-5(7x-6)+12x
We add all the numbers together, and all the variables
12x+6(x-3)-5(7x-6)
We multiply parentheses
12x+6x-35x-18+30
We add all the numbers together, and all the variables
-17x+12
Back to the equation:
-(-17x+12)
-12x-(-17x+12)+27=0
We get rid of parentheses
-12x+17x-12+27=0
We add all the numbers together, and all the variables
5x+15=0
We move all terms containing x to the left, all other terms to the right
5x=-15
x=-15/5
x=-3
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