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6(3x+2)-5(6x-1=3(x-8)-5(7x-6)+9x
We move all terms to the left:
6(3x+2)-5(6x-1-(3(x-8)-5(7x-6)+9x)=0
We multiply parentheses
18x-5(6x-1-(3(x-8)-5(7x-6)+9x)+12=0
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