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6(3x+1)=2(5x+3)
We move all terms to the left:
6(3x+1)-(2(5x+3))=0
We multiply parentheses
18x-(2(5x+3))+6=0
We calculate terms in parentheses: -(2(5x+3)), so:We get rid of parentheses
2(5x+3)
We multiply parentheses
10x+6
Back to the equation:
-(10x+6)
18x-10x-6+6=0
We add all the numbers together, and all the variables
8x=0
x=0/8
x=0
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