6(3x+1)=2(4x+3)+2(x+4)

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Solution for 6(3x+1)=2(4x+3)+2(x+4) equation:



6(3x+1)=2(4x+3)+2(x+4)
We move all terms to the left:
6(3x+1)-(2(4x+3)+2(x+4))=0
We multiply parentheses
18x-(2(4x+3)+2(x+4))+6=0
We calculate terms in parentheses: -(2(4x+3)+2(x+4)), so:
2(4x+3)+2(x+4)
We multiply parentheses
8x+2x+6+8
We add all the numbers together, and all the variables
10x+14
Back to the equation:
-(10x+14)
We get rid of parentheses
18x-10x-14+6=0
We add all the numbers together, and all the variables
8x-8=0
We move all terms containing x to the left, all other terms to the right
8x=8
x=8/8
x=1

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