6(3x+1)-14(2-4x)=3(5x-4)+7(7x)

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Solution for 6(3x+1)-14(2-4x)=3(5x-4)+7(7x) equation:



6(3x+1)-14(2-4x)=3(5x-4)+7(7x)
We move all terms to the left:
6(3x+1)-14(2-4x)-(3(5x-4)+7(7x))=0
We add all the numbers together, and all the variables
6(3x+1)-14(-4x+2)-(3(5x-4)+77x)=0
We multiply parentheses
18x+56x-(3(5x-4)+77x)+6-28=0
We calculate terms in parentheses: -(3(5x-4)+77x), so:
3(5x-4)+77x
We add all the numbers together, and all the variables
77x+3(5x-4)
We multiply parentheses
77x+15x-12
We add all the numbers together, and all the variables
92x-12
Back to the equation:
-(92x-12)
We add all the numbers together, and all the variables
74x-(92x-12)-22=0
We get rid of parentheses
74x-92x+12-22=0
We add all the numbers together, and all the variables
-18x-10=0
We move all terms containing x to the left, all other terms to the right
-18x=10
x=10/-18
x=-5/9

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